5g^2+14g+9=0

Solution for 5g^2+14g+9=0 equation:

5g^2+14g+9=0

a = 5; b = 14; c = +9;
Δ = b2-4ac
Δ = 142-4·5·9
Δ = 16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$g_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$g_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{16}=4$
$g_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(14)-4}{2*5}=\frac{-18}{10}
=-1+4/5
$
$g_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(14)+4}{2*5}=\frac{-10}{10}
=-1
$